(来学网)某药物t1/2=0.93h,Css=0.4μg/ml,V=6.5L,则零级静脉滴注k0取值是
  • A.
    (来学网)0.015mg/h
  • B.
    (来学网)0.068mg/h
  • C.
    (来学网)0.86mg/h
  • D.
    (来学网)1.94mg/h
  • E.
    (来学网)2.28mg/h
正确答案:
D
答案解析:
t1/2=0.693/k,即k=0.693/t1/2=0.693/0.93h=0.745h^(-1),静脉滴注稳态浓度公式为:Css=k0/kV,带入数据,k0=Css·kV=0.4ug/ml×0.745h^(-1)×6.5L=1.937mg/h≈1.94mg/h。